Certainly you cannot do it by generic file date information. Creation and modification dates relate to the file, not the original movie. The file column Media created likewise only exists for videos you have shot with your phone or camera, not a film you have downloaded.
Here is a possible workaround for year information. Many downloaded movies include the film year in the filename (in brackets or otherwise) as such:
Star Wars The Empire Strikes Back (1980) 720i.mkv Brazil.1985.720p.X264.mp4 WarGames 1983.mp4
Obviously there's no guarantee that year is part of the filename, but if you can find 4 digits somewhere in the name, it usually is the desired information. So we just need to extract 4 numbers from a filename, that can appear anywhere (start, middle or end of name). A tall order you say? Not really, it is quite easy using xplorer² programmable file properties. Use Customize > Programmable > Add new menu command and type in the following definition:
INT( MID(${Name}, FIND(${Name}, '\d\d\d\d'), 4) )
For years its more robust to use this regular expression that excludes non-year 4-digit numbers '[12]\d\d\d'
This complex expression searches for 4 numbers in ${Name} using FIND function ('\d\d\d\d' is a regular expression that matches 4 digits exactly). If the search is successful, it extracts the 4 digits using MID function. Finally the text is converted to an integer number using INT function.
Converting to integer isn't required but it helps if you want to search for a range of years
The complex recursive expression can broken down to its constituents so that it is easier to digest, unwinding the inner function calls using intermediary variables. (// are comment lines)
Note how regular expressions are defined using single ears '\d\d\d\d'
// suppose the current filename is "WarGames 1983.mp4" n = FIND(${Name}, '\d\d\d\d') // n=10, the offset where the 4 numbers start str = MID(${Name}, n, 4) // extract 4 letters from position n (str="1983") year = INT(str) // 1983 is the end result
Some assembly required <g>
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